1-(2/t)-(48/t^2)=0

Solution for 1-(2/t)-(48/t^2)=0 equation:

D( t )

t^2 = 0

t = 0

t^2 = 0

t^2 = 0

1*t^2 = 0 // : 1

t^2 = 0

t = 0

t = 0

t = 0

t in (-oo:0) U (0:+oo)

1-(2/t)-(48/(t^2)) = 0

1-2*t^-1-48*t^-2 = 0

t_1 = t^-1

1-48*t_1^2-2*t_1^1 = 0

1-48*t_1^2-2*t_1 = 0

DELTA = (-2)^2-(-48*1*4)

DELTA = 196

DELTA > 0

t_1 = (196^(1/2)+2)/(-48*2) or t_1 = (2-196^(1/2))/(-48*2)

t_1 = -1/6 or t_1 = 1/8

t_1 = -1/6

t^-1+1/6 = 0

1*t^-1 = -1/6 // : 1

t^-1 = -1/6

-1 < 0

1/(t^1) = -1/6 // * t^1

1 = -1/6*t^1 // : -1/6

-6 = t^1

t = -6

t_1 = 1/8

t^-1-1/8 = 0

1*t^-1 = 1/8 // : 1

t^-1 = 1/8

-1 < 0

1/(t^1) = 1/8 // * t^1

1 = 1/8*t^1 // : 1/8

8 = t^1

t = 8

t in { -6, 8 }